For a graph G and a set of graphs H, we say that G is H-free if no induced subgraph of G is isomorphic to a member of H. Given an integer P> 0, a graph G, and a set of graphs F, we say that G admits an (F, P)-partition if the vertex set of G can be partitioned into P subsets X1,..., XP, so that for every i ∈ {1,..., P}, either |Xi | = 1, or the subgraph of G induced by Xi is {F}-free for some F ∈ F. Our first result is the following. For every pair (H,J) of graphs such that H is the disjoint union of two graphs H1 and H2, and the complement J c of J is the disjoint union of two graphs Jc1 and J c 2, there exists an integer P> 0 such that every {H,J}-free graph has an ({H1, H2, J1, J2}, P)-partition. A similar result holds for tournam...
28 pages, 4 figuresWe resolve the computational complexity of Graph Isomorphism for classes of graph...
AbstractWe consider the following generalization of split graphs: A graph is said to be a (k,ℓ)-grap...
AbstractWe prove the following conjecture of A. Frank (Fifth British Combinatorial Conference, Aberd...
For a graph G and a set of graphs H, we say that G is H-free if no induced subgraph of G is isomorph...
For a graph G and a set of graphs H, we say that G is H-free if no induced subgraph of G is isomorph...
For a graph $G$ and a set of graphs $\mathcal{H}$, we say that $G$ is {\em $\mathcal{H}$-free} if no...
A graph is H-free if it has no induced subgraph isomorphic to H, and |G| denotes the number of verti...
A graph is H-free if it has no induced subgraph isomorphic to H. We continue a study into the bounde...
A graph is H-free if it has no induced subgraph isomorphic to H. We continue a study into the bounde...
A graph is called an $(r,k)$-graph if its vertex set can be partitioned into $r$ parts of size at mo...
A graph G=(V,E) is partitionable if there exists a partition {A,B} of V such that A induces a disjoi...
International audienceAbstract We resolve the computational complexity of Graph Isomorphism for clas...
International audienceAbstract We resolve the computational complexity of Graph Isomorphism for clas...
A graph $G$ is $H$-free if any subset of $V(G)$ does not induce a subgraph of $G$ that is isomorphic...
We almost completely resolve the computational complexity of Graph Isomorphism for classes of graphs...
28 pages, 4 figuresWe resolve the computational complexity of Graph Isomorphism for classes of graph...
AbstractWe consider the following generalization of split graphs: A graph is said to be a (k,ℓ)-grap...
AbstractWe prove the following conjecture of A. Frank (Fifth British Combinatorial Conference, Aberd...
For a graph G and a set of graphs H, we say that G is H-free if no induced subgraph of G is isomorph...
For a graph G and a set of graphs H, we say that G is H-free if no induced subgraph of G is isomorph...
For a graph $G$ and a set of graphs $\mathcal{H}$, we say that $G$ is {\em $\mathcal{H}$-free} if no...
A graph is H-free if it has no induced subgraph isomorphic to H, and |G| denotes the number of verti...
A graph is H-free if it has no induced subgraph isomorphic to H. We continue a study into the bounde...
A graph is H-free if it has no induced subgraph isomorphic to H. We continue a study into the bounde...
A graph is called an $(r,k)$-graph if its vertex set can be partitioned into $r$ parts of size at mo...
A graph G=(V,E) is partitionable if there exists a partition {A,B} of V such that A induces a disjoi...
International audienceAbstract We resolve the computational complexity of Graph Isomorphism for clas...
International audienceAbstract We resolve the computational complexity of Graph Isomorphism for clas...
A graph $G$ is $H$-free if any subset of $V(G)$ does not induce a subgraph of $G$ that is isomorphic...
We almost completely resolve the computational complexity of Graph Isomorphism for classes of graphs...
28 pages, 4 figuresWe resolve the computational complexity of Graph Isomorphism for classes of graph...
AbstractWe consider the following generalization of split graphs: A graph is said to be a (k,ℓ)-grap...
AbstractWe prove the following conjecture of A. Frank (Fifth British Combinatorial Conference, Aberd...