Under the hypothesis that NP does not have p-measure 0 (roughly, that NP contains more than a negligible subset of exponential time), it is shown that there is a language that is =PT-complete ("Cook complete"), but not =Pm-complete ("Karp-Levin complete"), for NP. This conclusion, widely believed to be true, is not known to follow from P ¿ NP or other traditional complexity-theoretic hypotheses. Evidence is presented that "NP does not have p-measure 0" is a reasonable hypothesis with many credible consequences. Additional such consequences proven here include the separation of many truthtable reducibilities in NP (e.g., k queries versus k + 1 queries), the class separation E ¿ NE, and the existence of NP search problems that are not reducib...
P versus NP is considered as one of the most important open problems in computer science. This consi...
P versus NP is considered as one of the most important open problems in computer science. This consi...
This paper presents the following results on sets that are complete for $NP$. begin{enumerate} item...
Under the hypothesis that NP does not have p-measure 0 (roughly, that NP contains more than a neglig...
AbstractUnder the hypothesis that NP does not have p-measure 0 (roughly, that NP contains more than ...
Under the hypothesis that NP does not have p-measure 0 (roughly, that NP contains more than a neglig...
Under the hypothesis that NP does not have pmeasure roughly that NP contains more than a negligible...
Under the hypothesis that NP does not have p-measure 0 (roughly, that NP contains more than a neglig...
AbstractLutz (1993, “Proceedings of the Eight Annual Conference on Structure in Complexity Theory,” ...
We use hypotheses of structural complexity theory to separate various NP-com-pleteness notions. In p...
Under the hypothesis that NP does not have p-measure O (roughly, that NP contains more than a negli...
P versus NP is considered as one of the most important open problems in computer science. This consi...
A basic question about NP is whether or not search reduces in polynomial time to decision. We indica...
AbstractUnder the assumption that NP does not have p-measure 0, we investigate reductions to NP-comp...
AbstractWe prove that if for some ϵ>0, NP contains a set that is DTIME(2nϵ)-bi-immune, then NP conta...
P versus NP is considered as one of the most important open problems in computer science. This consi...
P versus NP is considered as one of the most important open problems in computer science. This consi...
This paper presents the following results on sets that are complete for $NP$. begin{enumerate} item...
Under the hypothesis that NP does not have p-measure 0 (roughly, that NP contains more than a neglig...
AbstractUnder the hypothesis that NP does not have p-measure 0 (roughly, that NP contains more than ...
Under the hypothesis that NP does not have p-measure 0 (roughly, that NP contains more than a neglig...
Under the hypothesis that NP does not have pmeasure roughly that NP contains more than a negligible...
Under the hypothesis that NP does not have p-measure 0 (roughly, that NP contains more than a neglig...
AbstractLutz (1993, “Proceedings of the Eight Annual Conference on Structure in Complexity Theory,” ...
We use hypotheses of structural complexity theory to separate various NP-com-pleteness notions. In p...
Under the hypothesis that NP does not have p-measure O (roughly, that NP contains more than a negli...
P versus NP is considered as one of the most important open problems in computer science. This consi...
A basic question about NP is whether or not search reduces in polynomial time to decision. We indica...
AbstractUnder the assumption that NP does not have p-measure 0, we investigate reductions to NP-comp...
AbstractWe prove that if for some ϵ>0, NP contains a set that is DTIME(2nϵ)-bi-immune, then NP conta...
P versus NP is considered as one of the most important open problems in computer science. This consi...
P versus NP is considered as one of the most important open problems in computer science. This consi...
This paper presents the following results on sets that are complete for $NP$. begin{enumerate} item...