F.H. Jackson defined a q-analogue of the factorial n! = 1∙2∙3 ⋯ n as (n!)q = 1∙ (1 + q) ∙ (1 + q + q2) ⋯ (1 + q + q2 + ⋯ +qn-1) which becomes the ordinary factorial as q → 1. He also defined the q-gamrna function as (FORMULA PRESENTED) and (FORMULA PRESENTED) where (FORMULA PRESENTED) It is known that if q → 1, Γq(x)) → Γ(x), where Γ(x) is the ordinary gamma function. Clearly Γq(n + 1) = (n!)q, so that the q-gamma function does extend the q factorial to non integer values of n. We will obtain an asymptotic expansion of Γq(z) as |z| →∞ in the right halfplane, which is uniform as q →1, and when q → 1, the asymptotic expansion becomes Stirling’s formula. © 1984 Rocky Mountain Mathematics Consortium
This is a continuation of [19], where we presented an extension of the q-hypergeometric function wit...
We revisit the q-deformed counterpart of the Zassenhaus formula, expressing the Jackson q-exponentia...
In 1997 Bhargava generalized the factorial sequence to factorials in any Dedekind domain. He asked ...
We give an asymptotic expansion (the higher Stirling formula) and an infinite product representation...
AbstractSome years ago Gessel [8] gave a q-analogue of the celebrated exponential formula. We presen...
Abstract. We present new short proofs for both Stirlings formula and Stir-lings formula for the Gamm...
In this paper, we establish more properties for the q-analogue of the unied generalization of Stirli...
The note gives a new approximation to the Stirling expansion for n!, with an application to the comp...
Our goal is to prove the following asymptotic estimate for n!, called Stirling’s formula. Theorem 1....
학위논문 (석사)-- 서울대학교 대학원 : 수리과학부, 2013. 2. 김영원.The gamma function, introduced by the Swiss mathematicia...
For |q| ≠ 1, the integral definition of the gamma function in terms of the exponential function is g...
We calculated the optimal values of the real parameters $a$ and $b$ in such a way that the asymptoti...
AbstractThe qs-differences of the non-central generalized q-factorials of t of order n, scale parame...
A q-analogue of a formula of G.N. Watson that gives the product of two non-terminating Gaussian hype...
AbstractWe give a simple proof of the continued fraction expansions of the ordinary generating funct...
This is a continuation of [19], where we presented an extension of the q-hypergeometric function wit...
We revisit the q-deformed counterpart of the Zassenhaus formula, expressing the Jackson q-exponentia...
In 1997 Bhargava generalized the factorial sequence to factorials in any Dedekind domain. He asked ...
We give an asymptotic expansion (the higher Stirling formula) and an infinite product representation...
AbstractSome years ago Gessel [8] gave a q-analogue of the celebrated exponential formula. We presen...
Abstract. We present new short proofs for both Stirlings formula and Stir-lings formula for the Gamm...
In this paper, we establish more properties for the q-analogue of the unied generalization of Stirli...
The note gives a new approximation to the Stirling expansion for n!, with an application to the comp...
Our goal is to prove the following asymptotic estimate for n!, called Stirling’s formula. Theorem 1....
학위논문 (석사)-- 서울대학교 대학원 : 수리과학부, 2013. 2. 김영원.The gamma function, introduced by the Swiss mathematicia...
For |q| ≠ 1, the integral definition of the gamma function in terms of the exponential function is g...
We calculated the optimal values of the real parameters $a$ and $b$ in such a way that the asymptoti...
AbstractThe qs-differences of the non-central generalized q-factorials of t of order n, scale parame...
A q-analogue of a formula of G.N. Watson that gives the product of two non-terminating Gaussian hype...
AbstractWe give a simple proof of the continued fraction expansions of the ordinary generating funct...
This is a continuation of [19], where we presented an extension of the q-hypergeometric function wit...
We revisit the q-deformed counterpart of the Zassenhaus formula, expressing the Jackson q-exponentia...
In 1997 Bhargava generalized the factorial sequence to factorials in any Dedekind domain. He asked ...