1-Methyl-3-phenylthiourea

The title compound, C8H10N2S, was prepared by reaction of methylamine solution, KOH and phenyl-isothiocyanate in ethanol. It adopts a syn-Me and anti-Ph conformation relative to the C=S double bond. The dihedral angle between the N—C(=S)—N thiourea and phenyl planes is 67.83 (6)°. In the crystal, the molecules centrosymmetrical dimers by pairs of N(Ph)—H...S hydrogen bonds. The dimers are linked by N(Me)—H...S hydrogen bonds into layers parallel to (100)